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ANTENTOP- 02- 2003, # 003

The Wireless Power Transmission System


In a detailed analysis of forces involved Curry shows that radiators with a capacitance of .0053 microfarads operating at 100 KHz with signal generator output of 200 volts coupled with a biasing potential of 1000 volts will produce a force from its charge displacement of 26,500 dynes.[14]

On the receiving side Curry states that the charge gradient can be expected to attenuate substantially at even moderate distance from the point of transmission. As an example he notes that if a signal intensity of 10,600 dynes at the point of transmission is reduced one billion times the "standing wave of the signal energy will therefore be charged with a force differential of 1.06 x 10-5 dynes. Each dipole having a capacitance of .0053 microfarads produces a system capacitance of .00265 microfarads. The voltage developed in the receiving network is given by

e=square root (F/(C x 107)

which in this case equals .02 volts. As noted "this is substantially above the minimum requirements of signal intensity for the detection of electrical signal energies."[15]

With such a great amount of operational detail it would seem that this design should perform as claimed. The device, however, is not in widespread use 25 years after the issuing of the patent. This forces the conclusion that the device did not successfully propagate signals through the water. Why it would not will be made clear by examining the Tesla design for wireless communication. It will be shown that the dipole nature of the radiator and the inability to state the amount of attenuation over a given distance (it was simply given as a billion times weaker than the transmitted signal) point to a fundamental misunderstanding of the nature of electrostatic induction.

The shortcoming of the Curry design for an electrostatic communication system can be seen in the basic nature relationship existing between two points of charge.(See Figure 6)

Figure 6

Because lines of flux exist between two opposite charges a dipole transmitting antenna is not needed. Curry proposed a dipole in order to create a wave of

the proper length to be propagated through the medium. However, in electrostatics it is not necessary for flux lines to detach and close upon themselves to propagate an electric field. The field is established by the flux lines between the two points of charge. Curry misunderstood the nature of the electrostatic field. Once the field is established, a change in pressure on the charge will cause a variation in charge at the other end of the field - a displacement current.

Also, Tesla points out that a dipole is not needed to receive even low frequency signals in an electrostatic system. Tesla pictured his receivers with electrodes spaced a quarter wavelength apart but this was to charge an unpowered receiver as rapidly as possible. The receiver's capacitor would see maximum voltage changes, and, thus, would gain sufficient charge to power a device, if the ground electrodes had such a spacing. If, though, "the impulses are... are alternating, but sufficiently long in duration" they can be received by a single electrode that is turned on and off with the same period as the transmitter. Because the field's flux lines do not radiate but start at the transmitter and terminate on the receiver, the receiving structure does not have to be a specific shape or length.

His patent, then, also describes a through-the-earth, compact ELF communication system. Today's ELF antenna arrays, by contrast, require hundreds of square miles for their deployment.

Proof of Principle Test


This method of electrostatic communication can be tested by using a grounded, resonant electrostatic detector coupled to a standard communications receiver, encased in RF shielding to receive a signal. For demonstration purposes a commercial station transmitting on 1.16 MHz at 50KW, 40 miles away from the receiver could be used as the test source.

If the transmitter's antenna is feed at 50ohms impedance, the antenna current is:

The quarter wavelength period for 1.16 MHz is:

P = 1/4f

P = 1/(4)1.16x106

P = 2.16x10-7 sec.

The amount of charge in the antenna during the quarter period is:

Page 31


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